2x^2-30x+87.5=0

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Solution for 2x^2-30x+87.5=0 equation:



2x^2-30x+87.5=0
a = 2; b = -30; c = +87.5;
Δ = b2-4ac
Δ = -302-4·2·87.5
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{2}}{2*2}=\frac{30-10\sqrt{2}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{2}}{2*2}=\frac{30+10\sqrt{2}}{4} $

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